(3x-12)=(x+10)

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Solution for (3x-12)=(x+10) equation: 



(3x-12)=(x+10)

We move all terms to the left:

(3x-12)-((x+10))=0

We get rid of parentheses

3x-((x+10))-12=0



We calculate terms in parentheses: -((x+10)), so:

(x+10)

We get rid of parentheses

x+10

Back to the equation:

-(x+10)



We get rid of parentheses

3x-x-10-12=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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