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3x+11+x=2-5(3-2x)
We move all terms to the left:
3x+11+x-(2-5(3-2x))=0
We add all the numbers together, and all the variables
3x+x-(2-5(-2x+3))+11=0
We add all the numbers together, and all the variables
4x-(2-5(-2x+3))+11=0
We calculate terms in parentheses: -(2-5(-2x+3)), so:We get rid of parentheses
2-5(-2x+3)
determiningTheFunctionDomain -5(-2x+3)+2
We multiply parentheses
10x-15+2
We add all the numbers together, and all the variables
10x-13
Back to the equation:
-(10x-13)
4x-10x+13+11=0
We add all the numbers together, and all the variables
-6x+24=0
We move all terms containing x to the left, all other terms to the right
-6x=-24
x=-24/-6
x=+4
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