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3x+1/5(5x-5)=-3x+-28
We move all terms to the left:
3x+1/5(5x-5)-(-3x+-28)=0
Domain of the equation: 5(5x-5)!=0We add all the numbers together, and all the variables
x∈R
3x+1/5(5x-5)-(-3x-28)=0
We get rid of parentheses
3x+1/5(5x-5)+3x+28=0
We multiply all the terms by the denominator
3x*5(5x-5)+3x*5(5x-5)+28*5(5x-5)+1=0
Wy multiply elements
15x^2(5+15x^2(5+140x(5+1=0
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