2x+4(x-2)=-3(4-x)+6

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Solution for 2x+4(x-2)=-3(4-x)+6 equation: 



2x+4(x-2)=-3(4-x)+6

We move all terms to the left:

2x+4(x-2)-(-3(4-x)+6)=0

We add all the numbers together, and all the variables

2x+4(x-2)-(-3(-1x+4)+6)=0

We multiply parentheses

2x+4x-(-3(-1x+4)+6)-8=0



We calculate terms in parentheses: -(-3(-1x+4)+6), so:

-3(-1x+4)+6

We multiply parentheses

3x-12+6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

6x-(3x-6)-8=0

We get rid of parentheses

6x-3x+6-8=0

We add all the numbers together, and all the variables

3x-2=0

We move all terms containing x to the left, all other terms to the right

3x=2

x=2/3

x=2/3

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