3x+1/4(20x-12)=7x+3

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Solution for 3x+1/4(20x-12)=7x+3 equation: 



3x+1/4(20x-12)=7x+3

We move all terms to the left:

3x+1/4(20x-12)-(7x+3)=0



Domain of the equation: 4(20x-12)!=0

x∈R



We get rid of parentheses

3x+1/4(20x-12)-7x-3=0

We multiply all the terms by the denominator


3x*4(20x-12)-7x*4(20x-12)-3*4(20x-12)+1=0

Wy multiply elements

12x^2(2-28x^2(2-12x(2+1=0

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