3/5x-4=2/3x+7

Solution for 3/5x-4=2/3x+7 equation:

3/5x-4=2/3x+7

We move all terms to the left:

3/5x-4-(2/3x+7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 3x+7)!=0

x∈R


We get rid of parentheses

3/5x-2/3x-7-4=0

We calculate fractions


9x/15x^2+(-10x)/15x^2-7-4=0

We add all the numbers together, and all the variables

9x/15x^2+(-10x)/15x^2-11=0

We multiply all the terms by the denominator


9x+(-10x)-11*15x^2=0

Wy multiply elements

-165x^2+9x+(-10x)=0

We get rid of parentheses

-165x^2+9x-10x=0

We add all the numbers together, and all the variables

-165x^2-1x=0

a = -165; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-165)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-165}=\frac{0}{-330}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-165}=\frac{2}{-330}
=-1/165
$