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3x+1/2x=-28
We move all terms to the left:
3x+1/2x-(-28)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3x+1/2x+28=0
We multiply all the terms by the denominator
3x*2x+28*2x+1=0
Wy multiply elements
6x^2+56x+1=0
a = 6; b = 56; c = +1;
Δ = b2-4ac
Δ = 562-4·6·1
Δ = 3112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3112}=\sqrt{4*778}=\sqrt{4}*\sqrt{778}=2\sqrt{778}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-2\sqrt{778}}{2*6}=\frac{-56-2\sqrt{778}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+2\sqrt{778}}{2*6}=\frac{-56+2\sqrt{778}}{12} $
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