3x+1-2(-2x-4)=3(x-3)

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Solution for 3x+1-2(-2x-4)=3(x-3) equation: 



3x+1-2(-2x-4)=3(x-3)

We move all terms to the left:

3x+1-2(-2x-4)-(3(x-3))=0

We multiply parentheses

3x+4x-(3(x-3))+8+1=0



We calculate terms in parentheses: -(3(x-3)), so:

3(x-3)

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We add all the numbers together, and all the variables

7x-(3x-9)+9=0

We get rid of parentheses

7x-3x+9+9=0

We add all the numbers together, and all the variables

4x+18=0

We move all terms containing x to the left, all other terms to the right

4x=-18

x=-18/4

x=-4+1/2

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