4(-2-2b)=3(-3b-3)

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Solution for 4(-2-2b)=3(-3b-3) equation: 



4(-2-2b)=3(-3b-3)

We move all terms to the left:

4(-2-2b)-(3(-3b-3))=0

We add all the numbers together, and all the variables

4(-2b-2)-(3(-3b-3))=0

We multiply parentheses

-8b-(3(-3b-3))-8=0



We calculate terms in parentheses: -(3(-3b-3)), so:

3(-3b-3)

We multiply parentheses

-9b-9

Back to the equation:

-(-9b-9)



We get rid of parentheses

-8b+9b+9-8=0

We add all the numbers together, and all the variables

b+1=0

We move all terms containing b to the left, all other terms to the right

b=-1

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