3x+1(10x-3)=6x+11(5x+7)

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Solution for 3x+1(10x-3)=6x+11(5x+7) equation: 



3x+1(10x-3)=6x+11(5x+7)

We move all terms to the left:

3x+1(10x-3)-(6x+11(5x+7))=0



We calculate terms in parentheses: -(6x+11(5x+7)), so:

6x+11(5x+7)

We multiply parentheses

6x+55x+77

We add all the numbers together, and all the variables

61x+77

Back to the equation:

-(61x+77)



We get rid of parentheses

3x+1(10x-3)-61x-77=0

We add all the numbers together, and all the variables

-58x+1(10x-3)-77=0

We move all terms containing x to the left, all other terms to the right

-58x+1(10x-3)=77

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