9/x=9/8x+1

Solution for 9/x=9/8x+1 equation:

9/x=9/8x+1

We move all terms to the left:

9/x-(9/8x+1)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 8x+1)!=0

x∈R


We get rid of parentheses

9/x-9/8x-1=0

We calculate fractions


72x/8x^2+(-9x)/8x^2-1=0

We multiply all the terms by the denominator


72x+(-9x)-1*8x^2=0

Wy multiply elements

-8x^2+72x+(-9x)=0

We get rid of parentheses

-8x^2+72x-9x=0

We add all the numbers together, and all the variables

-8x^2+63x=0

a = -8; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·(-8)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*-8}=\frac{-126}{-16}
=7+7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*-8}=\frac{0}{-16}
=0
$