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3x+(1x/4)=26
We move all terms to the left:
3x+(1x/4)-(26)=0
We add all the numbers together, and all the variables
3x+(+1x/4)-26=0
We get rid of parentheses
3x+1x/4-26=0
We multiply all the terms by the denominator
3x*4+1x-26*4=0
We add all the numbers together, and all the variables
x+3x*4-104=0
Wy multiply elements
x+12x-104=0
We add all the numbers together, and all the variables
13x-104=0
We move all terms containing x to the left, all other terms to the right
13x=104
x=104/13
x=8
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