P=(x*2)+((x+3)*2)

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Solution for P=(x*2)+((x+3)*2) equation: 



=(P*2)+((P+3)*2)

We move all terms to the left:

-((P*2)+((P+3)*2))=0

We add all the numbers together, and all the variables

-((+P*2)+((P+3)*2))=0



We calculate terms in parentheses: -((+P*2)+((P+3)*2)), so:

(+P*2)+((P+3)*2)

We get rid of parentheses

P*2+((P+3)*2)



We calculate terms in parentheses: +((P+3)*2), so:

(P+3)*2

We multiply parentheses

2P+6

Back to the equation:

+(2P+6)



Wy multiply elements

2P+(2P+6)

We get rid of parentheses

2P+2P+6

We add all the numbers together, and all the variables

4P+6

Back to the equation:

-(4P+6)



We get rid of parentheses

-4P-6=0

We move all terms containing P to the left, all other terms to the right

-4P=6

P=6/-4

P=-1+1/2

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