3x(x+44)=180

Solution for 3x(x+44)=180 equation:

3x(x+44)=180

We move all terms to the left:

3x(x+44)-(180)=0

We multiply parentheses

3x^2+132x-180=0

a = 3; b = 132; c = -180;
Δ = b2-4ac
Δ = 1322-4·3·(-180)
Δ = 19584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19584}=\sqrt{576*34}=\sqrt{576}*\sqrt{34}=24\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-24\sqrt{34}}{2*3}=\frac{-132-24\sqrt{34}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+24\sqrt{34}}{2*3}=\frac{-132+24\sqrt{34}}{6}
$