2(4z+4)-3(5z+5)=35

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Solution for 2(4z+4)-3(5z+5)=35 equation: 



2(4z+4)-3(5z+5)=35

We move all terms to the left:

2(4z+4)-3(5z+5)-(35)=0

We multiply parentheses

8z-15z+8-15-35=0

We add all the numbers together, and all the variables

-7z-42=0

We move all terms containing z to the left, all other terms to the right

-7z=42

z=42/-7

z=-6

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