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3x(x+3)=171
We move all terms to the left:
3x(x+3)-(171)=0
We multiply parentheses
3x^2+9x-171=0
a = 3; b = 9; c = -171;
Δ = b2-4ac
Δ = 92-4·3·(-171)
Δ = 2133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2133}=\sqrt{9*237}=\sqrt{9}*\sqrt{237}=3\sqrt{237}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{237}}{2*3}=\frac{-9-3\sqrt{237}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{237}}{2*3}=\frac{-9+3\sqrt{237}}{6} $
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