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3x+(9x-5)=163
We move all terms to the left:
3x+(9x-5)-(163)=0
We get rid of parentheses
3x+9x-5-163=0
We add all the numbers together, and all the variables
12x-168=0
We move all terms containing x to the left, all other terms to the right
12x=168
x=168/12
x=14
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