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3x(7x-15)=25
We move all terms to the left:
3x(7x-15)-(25)=0
We multiply parentheses
21x^2-45x-25=0
a = 21; b = -45; c = -25;
Δ = b2-4ac
Δ = -452-4·21·(-25)
Δ = 4125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4125}=\sqrt{25*165}=\sqrt{25}*\sqrt{165}=5\sqrt{165}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-5\sqrt{165}}{2*21}=\frac{45-5\sqrt{165}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+5\sqrt{165}}{2*21}=\frac{45+5\sqrt{165}}{42} $
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