2/3x+x=225

Solution for 2/3x+x=225 equation:

2/3x+x=225

We move all terms to the left:

2/3x+x-(225)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x+2/3x-225=0

We multiply all the terms by the denominator


x*3x-225*3x+2=0

Wy multiply elements

3x^2-675x+2=0

a = 3; b = -675; c = +2;
Δ = b2-4ac
Δ = -6752-4·3·2
Δ = 455601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-675)-\sqrt{455601}}{2*3}=\frac{675-\sqrt{455601}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-675)+\sqrt{455601}}{2*3}=\frac{675+\sqrt{455601}}{6}
$