3x(7x+20)=0

Solution for 3x(7x+20)=0 equation:

3x(7x+20)=0

We multiply parentheses

21x^2+60x=0

a = 21; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·21·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*21}=\frac{-120}{42}
=-2+6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*21}=\frac{0}{42}
=0
$