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(9x-22)=(3x+10)
We move all terms to the left:
(9x-22)-((3x+10))=0
We get rid of parentheses
9x-((3x+10))-22=0
We calculate terms in parentheses: -((3x+10)), so:We get rid of parentheses
(3x+10)
We get rid of parentheses
3x+10
Back to the equation:
-(3x+10)
9x-3x-10-22=0
We add all the numbers together, and all the variables
6x-32=0
We move all terms containing x to the left, all other terms to the right
6x=32
x=32/6
x=5+1/3
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