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3x(5x-2)-4(5x-2)=0
We multiply parentheses
15x^2-6x-20x+8=0
We add all the numbers together, and all the variables
15x^2-26x+8=0
a = 15; b = -26; c = +8;
Δ = b2-4ac
Δ = -262-4·15·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*15}=\frac{12}{30} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*15}=\frac{40}{30} =1+1/3 $
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