15=3(6b+7)+6(5b-1)

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Solution for 15=3(6b+7)+6(5b-1) equation: 



15=3(6b+7)+6(5b-1)

We move all terms to the left:

15-(3(6b+7)+6(5b-1))=0



We calculate terms in parentheses: -(3(6b+7)+6(5b-1)), so:

3(6b+7)+6(5b-1)

We multiply parentheses

18b+30b+21-6

We add all the numbers together, and all the variables

48b+15

Back to the equation:

-(48b+15)



We get rid of parentheses

-48b-15+15=0

We add all the numbers together, and all the variables

-48b=0

b=0/-48

b=0

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