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3x(5x+5)=60
We move all terms to the left:
3x(5x+5)-(60)=0
We multiply parentheses
15x^2+15x-60=0
a = 15; b = 15; c = -60;
Δ = b2-4ac
Δ = 152-4·15·(-60)
Δ = 3825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3825}=\sqrt{225*17}=\sqrt{225}*\sqrt{17}=15\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{17}}{2*15}=\frac{-15-15\sqrt{17}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{17}}{2*15}=\frac{-15+15\sqrt{17}}{30} $
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