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3(x+2)-4=5-7(x-1)
We move all terms to the left:
3(x+2)-4-(5-7(x-1))=0
We multiply parentheses
3x-(5-7(x-1))+6-4=0
We calculate terms in parentheses: -(5-7(x-1)), so:We add all the numbers together, and all the variables
5-7(x-1)
determiningTheFunctionDomain -7(x-1)+5
We multiply parentheses
-7x+7+5
We add all the numbers together, and all the variables
-7x+12
Back to the equation:
-(-7x+12)
3x-(-7x+12)+2=0
We get rid of parentheses
3x+7x-12+2=0
We add all the numbers together, and all the variables
10x-10=0
We move all terms containing x to the left, all other terms to the right
10x=10
x=10/10
x=1
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