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3x(4x-1)=180
We move all terms to the left:
3x(4x-1)-(180)=0
We multiply parentheses
12x^2-3x-180=0
a = 12; b = -3; c = -180;
Δ = b2-4ac
Δ = -32-4·12·(-180)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-93}{2*12}=\frac{-90}{24} =-3+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+93}{2*12}=\frac{96}{24} =4 $
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