7-(n-1)=2(n+3)

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Solution for 7-(n-1)=2(n+3) equation: 



7-(n-1)=2(n+3)

We move all terms to the left:

7-(n-1)-(2(n+3))=0

We get rid of parentheses

-n-(2(n+3))+1+7=0



We calculate terms in parentheses: -(2(n+3)), so:

2(n+3)

We multiply parentheses

2n+6

Back to the equation:

-(2n+6)



We add all the numbers together, and all the variables

-1n-(2n+6)+8=0

We get rid of parentheses

-1n-2n-6+8=0

We add all the numbers together, and all the variables

-3n+2=0

We move all terms containing n to the left, all other terms to the right

-3n=-2

n=-2/-3

n=2/3

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