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3x(4x-1)+90=180
We move all terms to the left:
3x(4x-1)+90-(180)=0
We add all the numbers together, and all the variables
3x(4x-1)-90=0
We multiply parentheses
12x^2-3x-90=0
a = 12; b = -3; c = -90;
Δ = b2-4ac
Δ = -32-4·12·(-90)
Δ = 4329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4329}=\sqrt{9*481}=\sqrt{9}*\sqrt{481}=3\sqrt{481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{481}}{2*12}=\frac{3-3\sqrt{481}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{481}}{2*12}=\frac{3+3\sqrt{481}}{24} $
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