3x(2x+x)=x(3x-2)-24

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Solution for 3x(2x+x)=x(3x-2)-24 equation: 



3x(2x+x)=x(3x-2)-24

We move all terms to the left:

3x(2x+x)-(x(3x-2)-24)=0

We add all the numbers together, and all the variables

3x(+3x)-(x(3x-2)-24)=0

We multiply parentheses

9x^2-(x(3x-2)-24)=0



We calculate terms in parentheses: -(x(3x-2)-24), so:

x(3x-2)-24

We multiply parentheses

3x^2-2x-24

Back to the equation:

-(3x^2-2x-24)



We get rid of parentheses

9x^2-3x^2+2x+24=0

We add all the numbers together, and all the variables

6x^2+2x+24=0

a = 6; b = 2; c = +24;
Δ = b2-4ac
Δ = 22-4·6·24
Δ = -572
Delta is less than zero, so there is no solution for the equation

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