3x-5x(x-5)=8+3x+3

Solution for 3x-5x(x-5)=8+3x+3 equation:

3x-5x(x-5)=8+3x+3

We move all terms to the left:

3x-5x(x-5)-(8+3x+3)=0

We add all the numbers together, and all the variables

3x-5x(x-5)-(3x+11)=0

We multiply parentheses

-5x^2+3x+25x-(3x+11)=0

We get rid of parentheses

-5x^2+3x+25x-3x-11=0

We add all the numbers together, and all the variables

-5x^2+25x-11=0

a = -5; b = 25; c = -11;
Δ = b2-4ac
Δ = 252-4·(-5)·(-11)
Δ = 405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{405}=\sqrt{81*5}=\sqrt{81}*\sqrt{5}=9\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-9\sqrt{5}}{2*-5}=\frac{-25-9\sqrt{5}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+9\sqrt{5}}{2*-5}=\frac{-25+9\sqrt{5}}{-10}
$