3x(2x+5)-4=0

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Solution for 3x(2x+5)-4=0 equation:



3x(2x+5)-4=0
We multiply parentheses
6x^2+15x-4=0
a = 6; b = 15; c = -4;
Δ = b2-4ac
Δ = 152-4·6·(-4)
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{321}}{2*6}=\frac{-15-\sqrt{321}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{321}}{2*6}=\frac{-15+\sqrt{321}}{12} $

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