7/10c-18-1/2c=-16

Solution for 7/10c-18-1/2c=-16 equation:

7/10c-18-1/2c=-16

We move all terms to the left:

7/10c-18-1/2c-(-16)=0


Domain of the equation: 10c!=0

c!=0/10

c!=0

c∈R



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We add all the numbers together, and all the variables

7/10c-1/2c-2=0

We calculate fractions


14c/20c^2+(-10c)/20c^2-2=0

We multiply all the terms by the denominator


14c+(-10c)-2*20c^2=0

Wy multiply elements

-40c^2+14c+(-10c)=0

We get rid of parentheses

-40c^2+14c-10c=0

We add all the numbers together, and all the variables

-40c^2+4c=0

a = -40; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-40)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-40}=\frac{-8}{-80}
=1/10
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-40}=\frac{0}{-80}
=0
$