3x(2x+16)=180

Solution for 3x(2x+16)=180 equation:

3x(2x+16)=180

We move all terms to the left:

3x(2x+16)-(180)=0

We multiply parentheses

6x^2+48x-180=0

a = 6; b = 48; c = -180;
Δ = b2-4ac
Δ = 482-4·6·(-180)
Δ = 6624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6624}=\sqrt{144*46}=\sqrt{144}*\sqrt{46}=12\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12\sqrt{46}}{2*6}=\frac{-48-12\sqrt{46}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12\sqrt{46}}{2*6}=\frac{-48+12\sqrt{46}}{12}
$