3m(m-12)=12m

Solution for 3m(m-12)=12m equation:

3m(m-12)=12m

We move all terms to the left:

3m(m-12)-(12m)=0

We add all the numbers together, and all the variables

-12m+3m(m-12)=0

We multiply parentheses

3m^2-12m-36m=0

We add all the numbers together, and all the variables

3m^2-48m=0

a = 3; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·3·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*3}=\frac{0}{6}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*3}=\frac{96}{6}
=16
$