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3x(2+x)=x(3x-2)-24=
We move all terms to the left:
3x(2+x)-(x(3x-2)-24)=0
We add all the numbers together, and all the variables
3x(x+2)-(x(3x-2)-24)=0
We multiply parentheses
3x^2+6x-(x(3x-2)-24)=0
We calculate terms in parentheses: -(x(3x-2)-24), so:We get rid of parentheses
x(3x-2)-24
We multiply parentheses
3x^2-2x-24
Back to the equation:
-(3x^2-2x-24)
3x^2-3x^2+6x+2x+24=0
We add all the numbers together, and all the variables
8x+24=0
We move all terms containing x to the left, all other terms to the right
8x=-24
x=-24/8
x=-3
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