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3x(2)+x/2=180
We move all terms to the left:
3x(2)+x/2-(180)=0
We add all the numbers together, and all the variables
3x^2+x/2-180=0
We multiply all the terms by the denominator
3x^2*2+x-180*2=0
We add all the numbers together, and all the variables
3x^2*2+x-360=0
Wy multiply elements
6x^2+x-360=0
a = 6; b = 1; c = -360;
Δ = b2-4ac
Δ = 12-4·6·(-360)
Δ = 8641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{8641}}{2*6}=\frac{-1-\sqrt{8641}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{8641}}{2*6}=\frac{-1+\sqrt{8641}}{12} $
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