x+(x+1)+(x+2)+(x+3)=362

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Solution for x+(x+1)+(x+2)+(x+3)=362 equation: 



x+(x+1)+(x+2)+(x+3)=362

We move all terms to the left:

x+(x+1)+(x+2)+(x+3)-(362)=0

We get rid of parentheses

x+x+x+x+1+2+3-362=0

We add all the numbers together, and all the variables

4x-356=0

We move all terms containing x to the left, all other terms to the right

4x=356

x=356/4

x=89

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