3x(1-x)=-5

Solution for 3x(1-x)=-5 equation:

3x(1-x)=-5

We move all terms to the left:

3x(1-x)-(-5)=0

We add all the numbers together, and all the variables

3x(-1x+1)-(-5)=0

We add all the numbers together, and all the variables

3x(-1x+1)+5=0

We multiply parentheses

-3x^2+3x+5=0

a = -3; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-3)·5
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{69}}{2*-3}=\frac{-3-\sqrt{69}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{69}}{2*-3}=\frac{-3+\sqrt{69}}{-6}
$