3(-2+2r)=-(-4-7r)+6

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Solution for 3(-2+2r)=-(-4-7r)+6 equation: 



3(-2+2r)=-(-4-7r)+6

We move all terms to the left:

3(-2+2r)-(-(-4-7r)+6)=0

We add all the numbers together, and all the variables

3(2r-2)-(-(-7r-4)+6)=0

We multiply parentheses

6r-(-(-7r-4)+6)-6=0



We calculate terms in parentheses: -(-(-7r-4)+6), so:

-(-7r-4)+6

We get rid of parentheses

7r+4+6

We add all the numbers together, and all the variables

7r+10

Back to the equation:

-(7r+10)



We get rid of parentheses

6r-7r-10-6=0

We add all the numbers together, and all the variables

-1r-16=0

We move all terms containing r to the left, all other terms to the right

-r=16

r=16/-1

r=-16

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