3(x+1)+4x+3=3(x+1)+4x+3=34

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Solution for 3(x+1)+4x+3=3(x+1)+4x+3=34 equation: 



3(x+1)+4x+3=3(x+1)+4x+3=34

We move all terms to the left:

3(x+1)+4x+3-(3(x+1)+4x+3)=0

We add all the numbers together, and all the variables

4x+3(x+1)-(3(x+1)+4x+3)+3=0

We multiply parentheses

4x+3x-(3(x+1)+4x+3)+3+3=0



We calculate terms in parentheses: -(3(x+1)+4x+3), so:

3(x+1)+4x+3

We add all the numbers together, and all the variables

4x+3(x+1)+3

We multiply parentheses

4x+3x+3+3

We add all the numbers together, and all the variables

7x+6

Back to the equation:

-(7x+6)



We add all the numbers together, and all the variables

7x-(7x+6)+6=0

We get rid of parentheses

7x-7x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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