2(7-2n)+3(n-3)=-(-4-7n)+6

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Solution for 2(7-2n)+3(n-3)=-(-4-7n)+6 equation: 



2(7-2n)+3(n-3)=-(-4-7n)+6

We move all terms to the left:

2(7-2n)+3(n-3)-(-(-4-7n)+6)=0

We add all the numbers together, and all the variables

2(-2n+7)+3(n-3)-(-(-7n-4)+6)=0

We multiply parentheses

-4n+3n-(-(-7n-4)+6)+14-9=0



We calculate terms in parentheses: -(-(-7n-4)+6), so:

-(-7n-4)+6

We get rid of parentheses

7n+4+6

We add all the numbers together, and all the variables

7n+10

Back to the equation:

-(7n+10)



We add all the numbers together, and all the variables

-1n-(7n+10)+5=0

We get rid of parentheses

-1n-7n-10+5=0

We add all the numbers together, and all the variables

-8n-5=0

We move all terms containing n to the left, all other terms to the right

-8n=5

n=5/-8

n=-5/8

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