3x(1-x)+12=-3x(x-3)

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Solution for 3x(1-x)+12=-3x(x-3) equation: 



3x(1-x)+12=-3x(x-3)

We move all terms to the left:

3x(1-x)+12-(-3x(x-3))=0

We add all the numbers together, and all the variables

3x(-1x+1)-(-3x(x-3))+12=0

We multiply parentheses

-3x^2+3x-(-3x(x-3))+12=0



We calculate terms in parentheses: -(-3x(x-3)), so:

-3x(x-3)

We multiply parentheses

-3x^2+9x

Back to the equation:

-(-3x^2+9x)



We get rid of parentheses

-3x^2+3x^2-9x+3x+12=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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