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3x(1-2x)=16

We move all terms to the left:

3x(1-2x)-(16)=0

We add all the numbers together, and all the variables

3x(-2x+1)-16=0

We multiply parentheses

-6x^2+3x-16=0

a = -6; b = 3; c = -16;

Δ = b^{2}-4ac

Δ = 3^{2}-4·(-6)·(-16)

Δ = -375

Delta is less than zero, so there is no solution for the equation

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