3v-7+2(4v+5)=-3(v+1)

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Solution for 3v-7+2(4v+5)=-3(v+1) equation: 



3v-7+2(4v+5)=-3(v+1)

We move all terms to the left:

3v-7+2(4v+5)-(-3(v+1))=0

We multiply parentheses

3v+8v-(-3(v+1))+10-7=0



We calculate terms in parentheses: -(-3(v+1)), so:

-3(v+1)

We multiply parentheses

-3v-3

Back to the equation:

-(-3v-3)



We add all the numbers together, and all the variables

11v-(-3v-3)+3=0

We get rid of parentheses

11v+3v+3+3=0

We add all the numbers together, and all the variables

14v+6=0

We move all terms containing v to the left, all other terms to the right

14v=-6

v=-6/14

v=-3/7

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