2(u-6)=u+3-3(-5u-1)

Solution for 2(u-6)=u+3-3(-5u-1) equation:

2(u-6)=u+3-3(-5u-1)

We move all terms to the left:

2(u-6)-(u+3-3(-5u-1))=0

We multiply parentheses

2u-(u+3-3(-5u-1))-12=0


We calculate terms in parentheses: -(u+3-3(-5u-1)), so:

u+3-3(-5u-1)

determiningTheFunctionDomain
u-3(-5u-1)+3

We multiply parentheses

u+15u+3+3

We add all the numbers together, and all the variables

16u+6

Back to the equation:

-(16u+6)


We get rid of parentheses

2u-16u-6-12=0

We add all the numbers together, and all the variables

-14u-18=0

We move all terms containing u to the left, all other terms to the right

-14u=18

u=18/-14

u=-1+2/7