3v-2+4v=(v+5)

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Solution for 3v-2+4v=(v+5) equation: 



3v-2+4v=(v+5)

We move all terms to the left:

3v-2+4v-((v+5))=0

We add all the numbers together, and all the variables

7v-((v+5))-2=0



We calculate terms in parentheses: -((v+5)), so:

(v+5)

We get rid of parentheses

v+5

Back to the equation:

-(v+5)



We get rid of parentheses

7v-v-5-2=0

We add all the numbers together, and all the variables

6v-7=0

We move all terms containing v to the left, all other terms to the right

6v=7

v=7/6

v=1+1/6

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