-7-6(1+3z)=-18

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Solution for -7-6(1+3z)=-18 equation: 



-7-6(1+3z)=-18

We move all terms to the left:

-7-6(1+3z)-(-18)=0

We add all the numbers together, and all the variables

-6(3z+1)-7-(-18)=0

We add all the numbers together, and all the variables

-6(3z+1)+11=0

We multiply parentheses

-18z-6+11=0

We add all the numbers together, and all the variables

-18z+5=0

We move all terms containing z to the left, all other terms to the right

-18z=-5

z=-5/-18

z=5/18

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