2m=(4m-120)

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Solution for 2m=(4m-120) equation: 



2m=(4m-120)

We move all terms to the left:

2m-((4m-120))=0



We calculate terms in parentheses: -((4m-120)), so:

(4m-120)

We get rid of parentheses

4m-120

Back to the equation:

-(4m-120)



We get rid of parentheses

2m-4m+120=0

We add all the numbers together, and all the variables

-2m+120=0

We move all terms containing m to the left, all other terms to the right

-2m=-120

m=-120/-2

m=+60

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