3v+7-2(-8v-3)=5(v-1)

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Solution for 3v+7-2(-8v-3)=5(v-1) equation: 



3v+7-2(-8v-3)=5(v-1)

We move all terms to the left:

3v+7-2(-8v-3)-(5(v-1))=0

We multiply parentheses

3v+16v-(5(v-1))+6+7=0



We calculate terms in parentheses: -(5(v-1)), so:

5(v-1)

We multiply parentheses

5v-5

Back to the equation:

-(5v-5)



We add all the numbers together, and all the variables

19v-(5v-5)+13=0

We get rid of parentheses

19v-5v+5+13=0

We add all the numbers together, and all the variables

14v+18=0

We move all terms containing v to the left, all other terms to the right

14v=-18

v=-18/14

v=-1+2/7

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