1/2(x-6)=1/3(x+12)

Solution for 1/2(x-6)=1/3(x+12) equation:

1/2(x-6)=1/3(x+12)

We move all terms to the left:

1/2(x-6)-(1/3(x+12))=0


Domain of the equation: 2(x-6)!=0

x∈R



Domain of the equation: 3(x+12))!=0

x∈R


We calculate fractions


(3xx/(2(x-6)*3(x+12)))+(-2xx/(2(x-6)*3(x+12)))=0


We calculate terms in parentheses: +(3xx/(2(x-6)*3(x+12))), so:

3xx/(2(x-6)*3(x+12))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-2xx/(2(x-6)*3(x+12))), so:

-2xx/(2(x-6)*3(x+12))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)


We get rid of parentheses

3xx-2xx=0